A charge of 1.5 × 10^15 coulombs moves from point A to a lower potential at point B. The electric field is uniform at 2.5 × 10^-5 newtons/coulomb and the distance along the field lines between the two points is 1.7 × 10^-2 meters. What is the work done?

Question

jfraser · Answer

use W = q*E*Dx

anonymous · Answer

How? Im taking an online class and it does not explain anything that is understandable.

anonymous · Answer

could you set the equation up for me?

jfraser · Answer

the equation is set up for you. q is charge, E is the field, Dx is the distance moved.