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OpenStudy (anonymous):
is ; x^2-x<0 = 1 ?
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OpenStudy (anonymous):
you factor the x,s ; x(x-1)<0 -> x = 1 - am i right?
OpenStudy (tamtoan):
no, if x(x-1) <0 , then there can be 2 cases : either x < 0 AND x - 1 > 0 or x > 0 AND x -1 < 0 can you take it from here?
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