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OpenStudy (anonymous):
Find tan θ if sec θ = (sqrt. 37)/(6) and sin θ < 0
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OpenStudy (anonymous):
answer is 1/6 haci
OpenStudy (anonymous):
|dw:1358189281310:dw| that's what I have set up so far for tangent... mind explaining?
OpenStudy (anonymous):
how 'bout using the fact that tg^2(theta)+1=sec^2(theta)
OpenStudy (anonymous):
tg^2(theta)+1=37/36 /add (-1) tg^2(theta)=1/36 tg(theta)=+-1/6 I guess you can finish it
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