Question

What are the possible number of positive, negative, and complex zeros of f(x) = -x6 - x5- x4 - 4x3 - 12x2 + 12 ? (1 points)
Answer

Positive: 4, 2, or 0; Negative: 2 or 0; Complex: 6, 4, 2, or 0

Positive: 3 or 1; Negative: 3 or 1; Complex: 4, 2, or 0

Positive: 3 or 1; Negative: 2 or 0; Complex: 4, 2, or 0

Positive: 1; Negative: 5, 3, or 1; Complex: 4, 2, or 0

Answer 1

My answer is B

Answer 2

x1 = 0.8371
x2 = -1.1577
x3 = -1.336 + 1.1789i
x4 = -1.336 - 1.1789i
x5 = 0.9963 - 1.7053i
x6 = 0.9963 + 1.7053i

Answer 3

d is right answer
but also
ithink that question has a logic error

Answer 4

Slightly confused

Answer 5

oh, i see....thank you kind sir!!!!

Answer 6

what method you have to apply ?
for example bairstow method , bisection , ...