Question

Factor 2x^2+9x=7

Answer 1

I think first you have to write it as:\[2x^2+9x-7=0\]
If it can be factored, it will be "nice" numbers, so something like:\[(2x +a)(x+b)=0\]
Because you know that after FOILing (2x+a)(x+b) this has to be 2x²+9x-7, you now realize that:

1. ab=-7
2. 2b+a=9
3. a and b are "nice" (hopefully integer) numbers.

Can you find them?