Question

Please help. In the interval between 0degrees and 360degrees, what is the solution set of sin^2x-1=0 to the nearest degree?

Answer 1

\[\sin^2x=1 \]
\[sinx=\pm1\]
\[x=90^{o}, 270^{o}\]

Answer 2

is it 90degrees and 270degrees because its positive in certain quadrants?

Answer 3

and thank you for your help :)