Can someone help me on this please.The length of a retangle is 3 yd more than twice its width, the area of the retangle is 54yrd ^2. What are the deminisions of the retangle
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OpenStudy (anonymous):
NOTE : negative value of x should be rejected
OpenStudy (anonymous):
ok so to find the width & the length I went (12-w) w=24 12w-w^2=24 so far this is what I have. Am I in the right direction then?
OpenStudy (anonymous):
(3+2w)*w=54
OpenStudy (anonymous):
U should solve that
OpenStudy (anonymous):
yeah I can get it from here. I had 36 instead of 54.
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OpenStudy (anonymous):
(3+2w)*w=54
2w^2+3w-54=0
OpenStudy (anonymous):
2w^2+12w-9w-54=0
2w(w+6)-9(w+6)=0
(2w-9)(w+6)=0
OpenStudy (anonymous):
Now, can u?
OpenStudy (anonymous):
I am a little confused. Now that it is factored out, how can I get the length?
OpenStudy (anonymous):
either 2w-9=0
w=4.5 yard
Or w+6=0
w=-6 {since length cannot be megative it is rejected}
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OpenStudy (anonymous):
negative*
OpenStudy (anonymous):
ok. the negative threw me off. tk u for helping me on this.