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sqrt{11x-3}-2x=0
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\[\sqrt{11x-3}-2x=0\]Add 2x to both sides \[\sqrt{11x-3}=2x\]Square both sides, what do you get?
\[11x-3=4x^{2}\]
I really dont know what to do after that
Now, it's a quadratic equation \[4x^2 - 11x +3=0\]Can you solve it using quadratic formula?
thank you. i believe i should be able to. right now its come out to \[11\pm \sqrt{73}\]
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