rhombus ABCD has diagonals that intersect at E. DF is drawn perpendicular to DC and AD at D. With AB=10 cm,

Question

rhombus ABCD has diagonals that intersect at E. DF is drawn perpendicular to DC and AD at D. With AB=10 cm, <BCD = 60 degrees and FD= 4 cm, find the length of FE

shubhamsrg · Answer

Can you draw its figure?

anonymous · Answer

I dont know how ?

shubhamsrg · Answer

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shubhamsrg · Answer

DF is drawn perpendicular to DC
How is that possible ?
Please recheck the question ?

anonymous · Answer

That's what it says on my book. Maybe there's something wrong on it?

shubhamsrg · Answer

Seems likely to me, that something is wrong.

anonymous · Answer

Ok. Maybe I'll check it on other books.

Can you try this one ?

A square ABCD has one side that measures 6 in. A line CF is drawn perpendicular to both BC and and CD at C. if FC = 8 inches, find the length   of AF

anonymous · Answer

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