Question

I cannot wrap my head around this C++ question:
1. Write a program that finds the solutions, if any, to a given quadratic equation. A quadratic equation is any equation written in the form ax^2 + bx+ c. Keep in mind division by 0 is not permitted and the discriminant b^2-4ac cannot be negative. Use the quadratic formula. Note: if you feel for some reason you do not want to give me the C++ code then you can give me in pseudo-code.

Answer 1

This is literally exactly the code you need...just in java...not hard to figure out what it should be in c++ - change the system.outs to cout<<....etc...but this should help you out a lot!

public static void main(String[] args) {
System.out.print("This program solves a quadratic equation.\nEnter the coefficients a b c: ");
//get the three variables from user
Scanner reader= new Scanner (System.in);
double a=reader.nextDouble();
double b=reader.nextDouble();
double c=reader.nextDouble();

//calculate discriminate to determine how many solutions and calculate them
double disc=((b*b)-(4*a*c));
double quadP= (-b+Math.sqrt(disc))/(2*a)+0;
double quadM= (-b-Math.sqrt(disc))/(2*a)+0;

//equation with user's variables
System.out.format("Equation: %.2f*x^2 + %.2f*x + %.2f = 0\n", a, b, c);

if (a==0.0 && b==0 && c==0)
{
System.out.println("All real numbers are solutions.");
}

else if (a==0 && b==0)
{
System.out.println("There are no real solutions.");
}

else if (a==0)
{
double x= ((-c)/(b))+0;
System.out.format("There is one real solution: %.2f.\n", x);
}

else
{
if (disc<0.00)
{
System.out.println("There are no real solutions.");
}
else
{
if (disc>0.00)
{
System.out.format("There are two real solutions: %.2f, %.2f.%n", quadM, quadP);
}

if (disc==0.00)
{
System.out.format("There is one real solution: %.2f.%n", quadP);
}
{