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Identify type of conic, if any, and state its vertex or center. \[3x^2-12x+3y^2-6=0\]
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since the coefficient of the \(x^2\) terms is the same as the coefficient of the \(y^2\) term (they are both 3) you have a circle
so maybe circle with (2,0) then.. hmm
whoa my mistake
\[x^2-4x+y^2=-2\] \[(x-2)^2+y^2=2\] center is \((2,0)\) and radius is \(r=\sqrt2\)
got it! thanks!
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looks like you did it on your own, good work yw
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