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HELP!!!!!! PLEASE!!!!!!!! Find the volume of the solid obtained by rotating the region bounded by the curves y=x^2, y=3x and for x greater than or equal to 0 about the x axis.
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|dw:1358286724202:dw| use the disc method
okay so would you do the integral from 0 to three of pi(3x^2-x^4)dx?
\[\pi \int\limits_0^3(9x^2-x^4)\mathrm dx\]
Thanks I see what I did wrong now!
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