Question

can someone please help me in algebra 1?

Answer 1

Post a question c:

Answer 2

Suppose y varies directly with x, and y = 25 when x = 140. What is the value of x when y = 36? (1 point)
140
165
201.6
176

Answer 3

y varies directly with x,\[\large y=kx\]See how y and x have a direct relationship? They only differ by a constant, k.

When x=140, y=25.
We can use this information to find k.\[\large 25=k(140)\]To solve for k, divide both sides by 140.

Answer 4

Which changes our equation to,\[\large y=kx \qquad \rightarrow \qquad y=\frac{25}{140}x\]When y=36, what is x?\[\large 36=\frac{25}{140}x\]To solve for x, multiply both sides by, \(\huge \frac{140}{25}\)