Question

9.4 = 2In(1.8^x)

Answer 1

You have:\[2\ln(1.8^x)=9.4\]If you use the rule\[k \cdot \ln x=lnx^k\]you get\[\ln(1.8^x)^2=\ln(1.8^{2x})=9.4\]Next step would be losing the ln. Do you know how to do that?