Question

Jane is organizing a fundraiser to buy a ping-pong table for the community center. The table costs $500.00. Jane is asking contributors to pay for an equal share of the cost of the table. She already has five contributors lined up. What function models the cost per share, C, with respect to the number of contributors, n? How many contributors must Jane recruit in order for the cost of each share to be $20.00?

Answer 1

@hartnn can you help us with this question?

Answer 2

one table = 500$
one contributor's share =C
so., 5 contributor's share =5C
n contributor's share =nC

Answer 3

Is that the answer? or are you explaining it step by step ?

Answer 4

i think he's explaining it step by step

Answer 5

Okay cool.

Answer 6

so, we have nC=500
which gives us , cost per share C =500/n.

Answer 7

Okay @hartnn i see where your going. Is that my answer ?

Answer 8

for 2nd part,
you want C= 20,
so 20=500/n
find n

Answer 9

yes, that was 1st part answer.

Answer 10

okay so would you multiply 20 and 500 ?

Answer 11

or would it be 500 divided by 20

Answer 12

Yeah and 500/20 will equal 25

Answer 13

20=500/n
n=500/20 = 25

Answer 14

yes, she already had 5 contributors,
so she will need 20 more.

Answer 15

so thats the answer?

Answer 16

Thats what im thinking

Answer 17

Smokey, if 25 people pay $20 how much money do they give?

Answer 18

500

Answer 19

Thats what i got because i did 25*20 to queal 500

Answer 20

so, you got 500, right ?
yes, that was your answer.

Answer 21

Great :D

Answer 22

Snip answer @SmokeysTheName

Answer 23

k one sec

Answer 24

Got cha

Answer 25

ask if there are any doubts...

Answer 26

Okay @hartnn Thanks

Answer 27

thank you @hartnn

Answer 28

@Kayy_Drizzyy

Answer 29

welcome to both :)

Answer 30

can you answer another one @hartnn

Answer 31

i'll try.

Answer 32

ok ill tag you in it.

Answer 33

I got the same answer

Answer 34

did you push finish @SmokeysTheName ?

Answer 35

nooo we still havent figured out the hair dye one w/ percentages

Answer 36

Ohhhhhh yeah lets ask @hartnn for help on that one.

Answer 37

im getting help on that one before i submit it.

Answer 38

i did ill tag you in my question

Answer 39

great :)