Question

1)What method(s) would you choose to solve the equation:

x2 + 2x - 6 = 0


A. Square roots; there is no x-term.

B. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large. <<---

C. Factoring; the equation is easily factored.

D. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored.

2)What are the solutions of the equation?
c^2 - 10c = 0


A. 1, – squareroot10

B. 0, –10

C. 0, sqrt10

D. 0, 10 <<---

Answer 1

3)Use the discriminant to determine the number of real-number solutions for the equation:
8x2 + 8x + 2 = 0

A. one solution

B. two solutions <<<----

C. no solutions

D. infinitely many solutions

4)What are the solutions of the equation: z2 - 12z + 36 = 0?


A. -6, 6

B. 6, 6 <<<----

C. 6, -6

D. -6, -6

am i right?

Answer 2

for #1, the equation can't be factored, so that's true

but the reason it can't be factored isn't because the numbers are too big

the numbers -6 and 2 aren't big at all, so that's why I'm thinking B is off a bit

Answer 3

# 2 is correct

Answer 4

1) The answer is D. It can be seen that it cannot be B since the sentence is not generally regarded as true. The values of the coefficients are not large.

Answer 5

# 3 is incorrect

# 4 is correct

Answer 6

Thank you !!

Answer 7

Jim, I believe the discriminant implies there are two real solutions.

Answer 8

Scratch that, long day at uni. Discriminant is 0, I failed to get 4x2 =8 xD

Answer 9

for #3

D = b^2 - 4ac

D = 8^2 - 4(8)(2) ... plug in a = 8, b = 8 and c = 2

D = 64 - 32*2

D = 64 - 64

D = 0

So because the discriminant is 0, this means that there is only one solution. This solution shows up twice, but it's still considered one solution.

Answer 10

#1 is wrong.

Answer 11

right answer is D - Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored.