Question

The equation: y=144x+621, where y represents the cost in dollars and x=0 represents the year 1980.
Use the equation to find the cost of tuition and fees in 2002 and the year this cost will exceed $5250

Answer 1

If x=0 represents 1980 and we assume that x=years, then 2002 will be x=22 isn't it?
So y for x=22 will be
y=144*22+621=3789
So, in 2002 the cost of fees is $3789
Now, in part "b" you want to know the yeat this cost will EXCEED 5250, and that's an inequation
\[144\times x+621>y\]
For y=5250
\[144\times x+621>5250\]
\[x>\dfrac {5250-621} {144}\]
That's aprox x>32.15
So, in the year "33" the fee costs will have exceeded the quantity, and, if 1980 goes for x=0, x=33 means 1980+33=2013
Hope you understood D:

Answer 2

I understood part A but not so much on part B
a bit confuse on the inequation

Answer 3

ohhh never mind!! now that I look at it, the word EXCEED means bigger than 5250, so just replace y with 5250 and the orginal equation then find x

Answer 4

cuz u put 144 times X, made me confuse a little lol :)

Answer 5

Cool ;)