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Algebra
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CHECK MY ANSWER? A company sells a container of mixed nuts that is 12% peanuts and another container that is 60% peanuts. How many cups of each mixture would be needed to make 12 cups that is 40% peanuts? 4 cups of the 12% peanuts and 8 cups of the 60% peanuts 8 cups of the 12% peanuts and 4 cups of the 60% peanuts 5 cups of the 12% peanuts and 7 cups of the 60% peanuts 3 cups of the 12% peanuts and 9 cups of the 60% peanuts My answer is B if it's wrong can you please tell my the right one and how you got it.
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No you are correct it is, B. :)
Thx
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