2. Find the direct variation equation of the graph through the points (0, 0) and (1, -2). Write in y=kx form.(Points : 1)
y = 2x
y = -2x
y = 1/2 x
y = -1/2 x

3. Find the direct variation equation which passes through (0, 0) and (4, 1).(Points : 1)
y = 4x
y = -4x
y = 1/4 x
y = -1/4 x

Question

2. Find the direct variation equation of the graph through the points (0, 0) and (1, -2). Write in y=kx form.(Points : 1)  
       y = 2x
       y = -2x
       y = 1/2 x
       y = -1/2 x
  
    
3. Find the direct variation equation which passes through (0, 0) and (4, 1).(Points : 1)  
       y = 4x
       y = -4x
       y = 1/4 x
       y = -1/4 x

blurbendy · Answer

(-2 - 0) = -2
(1 - 0) = 1
y = -2x

2) (1 - 0) = 1
(4 - 0) = 4
y = 1/4x