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Simplify the expression. 1-cot x/ tan x -1 helppp
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\[\frac{ 1-cotx }{ tanx -1}=\frac{ 1-\frac{ 1 }{ \tan x } }{ \tan x -1 }=\frac{ \frac{ tanx-1 }{ tanx } }{ tanx-1 }\] \[=\frac{ tanx-1 }{ (tanx-1)tanx }=\frac{ 1 }{ tanx }=cotx\]
how did you get tanx-1/tan?
|dw:1358384724020:dw|
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