Question

https://dl.dropbox.com/u/63664351/Physics/D.C.%20Circuits.PNG

Answer 1

If the output is to be set at 6.0 V, then across the other section (A), the voltage drop needed to be 3.0 V.

At 0730, the resistance of the thermistor = 1.5 kΩ

The current flowing through section (A):

I=3V/1.5kΩ+1.5kΩ

I=0.001 A

Similarly, the same current flows through the section (B)

6.0 V =(Rv+1.5k)*(0.001A)

Rv=4.5kΩ

Answer 2

if correct please click best response.