7. Write the equation y - 4 = -2(x - 5) in slope-intercept form.(Points : 1)
y = -2x + 14
y = -2x + 5
y = -2x + 9
y = -2x + 6

8. If you are finding the line perpendicular to x + 3y = 5, what is the slope of the line?(Points : 1)
-3/5
1/3
3
-3

Question

7. Write the equation y - 4 = -2(x - 5) in slope-intercept form.(Points : 1)  
       y = -2x + 14
       y = -2x + 5
       y = -2x + 9
       y = -2x + 6
  
    
8. If you are finding the line perpendicular to x + 3y = 5, what is the slope of the line?(Points : 1)  
       -3/5
       1/3
       3
       -3

anonymous · Answer

it always works the same way
1) distributive law 
$$ y - 4 = -2(x - 5)$$
$$y-4=-2x+10$$ 2) solve for $y$
$$y=-2x+14$$

anonymous · Answer

the slope of $ax+by=c$ is $-\frac{a}{b}$ in your case the slope of 
$$x+3y=5$$ is $-\frac{1}{3}$ 
perpendicular line has slope that is the negative reciprocal

anonymous · Answer

negative reciprocal of $-\frac{1}{3}$ is $3$