Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = (x – 5); (–4, 3)

a) y = –3x + 15
b) y = –3x – 9
c} y = –4x + 3
d} y = –1/3x – 11

Answer 1

from the equation y + 2 = (x – 5); it is clear that its slope is 1
hence the slope of the line perpendicular to it is 1/-1=-1
and since it passes through (-4,3)

the eq of the reqd line is of the form
(y-3)=-1(x+4)

Answer 2

can u re -write ur question