Question

Find an equation of the tangent line to the graph of f at the given point. f(x) = 1/2xln(x^2), (-1, 0)

Answer 1

can u find f'(x)

Answer 2

well, would it be: 1/2(1)(1/x^2)(2x) ?

Answer 3

U need to use product rule

Answer 4

ok so would f(x) be 1/2x and g(x) be ln(x^2) ?

Answer 5

yes

Answer 6

1/2(ln(x^2))+(1/2(x))(1/x^2)(2x) ?