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Mathematics 7 Online
OpenStudy (anonymous):

1 2 ________ - ________ + x+1 (x+1)² 3 ________ x²-1

OpenStudy (anonymous):

If I'm not mistaken, this is another way you could write it. 1/(x+1) - 2/[(x+1)(x+1)] + 3/[(x-1)(x+1)]

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