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From a boat on the river below a dam, the angle of elevation to the top of the dam is 11 degrees 56'. If the dam is 1044 ft above the level of the river, how far is the boat from the base of the dam?
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i did \[x=1044~cos(11degrees56')\]and got 1021.438 ft but apparently the answer is 4939.890 ft ....??
@abb0t
@hartnn
figure ?
|dw:1358405606082:dw|
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\[cos~11~degrees~56'={x\over1044}\]
use tan ratio
tan = opposite/adjacent
WOOWW ...sorry i just realized
i was thinking 1044 was the hypotenuse....oh gosh
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happens :)
too often :P
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