Question

evaluate the integrals:>> integral sign sin 3x dx

Answer 1

do you know \[\int \sin ydy =... ?\]

Answer 2

put t=3x

Answer 3

then just do normal integration

Answer 4

ahm..."???"

Answer 5

yes, first tell what u get after u put t=3x
dt =... ?

Answer 6

3dx

Answer 7

yes, so dx = dt/3
so whats your new integral ?>

Answer 8

\[(1/3) \int \sin t dt = .. ?\]