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Solve the exponental equation. (1/16)=64^4x-3 work if possible
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Observe:\[\dfrac{1}{16} = 16^{-1} = 4^{-2}\]and\[64^{4x - 3}=(4^3)^{4x - 3} =4^{12x - 9}\]
im still confused, im sorry im horrible at this
Notice that:\[4^{-2} = 4^{12x - 9}\]
okay so what do i do after that?
Then that means,\[-2 = 12x - 9\]
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