Check my answer. Question: Write the equation that describes the line in slope-intercept form.slope = 4, point (3, –2) is on the line.
My answer: So first we use the point slope form. y - y1 = m (x - x1) = y - 3 = 4 (x - (- 2) = y - 3 = 4x + 8. Now we add 3 to both sides y - 3 + 3 = 4x + 8 + 3 = y = 4x + 11.

Question

Check my answer. Question: Write the equation that describes the line in slope-intercept form.slope = 4, point (3, –2) is on the line.
My answer:  So first we use the point slope form. y - y1 = m (x - x1) = y - 3 = 4 (x - (- 2) = y - 3 = 4x + 8. Now we add 3 to both sides y - 3 + 3 = 4x + 8 + 3 = y = 4x + 11.

anonymous · Answer

You accidenatlly used x, as y and vice versa

anonymous · Answer

My bad. Is this correct now?  y - ( -2) = 4 (x - 3) = y + 2 = 4x - 12. Now we subtract 2 from both sides y + 2 - 2 = 4x - 12 - 2 = y = 4x - 13.

anonymous · Answer

Not quite. -12-2=14. but other than that. You are right.

anonymous · Answer

i meant -14 btw

anonymous · Answer

Thanks

anonymous · Answer

Anytime