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Solve x2 + 9x = -3
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add 3 to both sides, and you get a quadratic equation of the form : \[ax^2+bx+c=0\]
what do you get after adding 3 on both sides ?
12x and 0
umm, nopes. x^2+9x =-3 x^2 +9x +3 = -3+3 x^2 +9x +3 =0 got this ?
ohh...
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now, Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
could you find the values of a,b,c ?
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