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Mathematics 12 Online
OpenStudy (anonymous):

Solve x2 + 9x = -3

hartnn (hartnn):

add 3 to both sides, and you get a quadratic equation of the form : \[ax^2+bx+c=0\]

hartnn (hartnn):

what do you get after adding 3 on both sides ?

OpenStudy (anonymous):

12x and 0

hartnn (hartnn):

umm, nopes. x^2+9x =-3 x^2 +9x +3 = -3+3 x^2 +9x +3 =0 got this ?

OpenStudy (anonymous):

ohh...

hartnn (hartnn):

now, Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

hartnn (hartnn):

could you find the values of a,b,c ?

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