simplify the rational expression. State any restrictions on the variable. q^2 + 11q +24/q^2 - 5q - 24
@tcarroll010
It might help to simplify by factoring the numerator and denominator and cross cancelling.
\[\frac{ (x+3)(x+8) }{ (x+3)(x-8) } = \]
\[\frac{ (q + 8)\cancel {(q + 3)} }{ (q - 8)\cancel {(q + 3)} } = \frac{ q + 8 }{ q - 8 }\]and you cannot have q =8 or q = -3
How did you do that crossing out?! :O
First, good luck in all of youstudies and thx for the recognition! Second, this box uses Latex formatting, so I did a backslash cancel and put what I wanted cancelled in between curly braces. Try it!
I spelled out backslash but when you use it, you just use the symbol, then the word cancel, then followed by what you want to cancel inside curly braces.
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