Question

is the integral of x/x^2+3 equal to
1/2ln[x^2+3]+C?

Answer 1

Using the substitution x^2 + 3 = u

du = 2x dx

xdx = 1/2 du

so it reduces to 1/2 int {1/u} du = 1/2 ln|x^2 + 3| + C

so yes, you're correct :)

Answer 2

YAYYYY, did that one myself...hoowah

Answer 3

well done, i'm proud :)