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Precalculus 17 Online
OpenStudy (anonymous):

how would i verify secxcscx-tanx=cotx

OpenStudy (slaaibak):

Let's first write it out: \[{1 \over \cos x} \times {1 \over \sin x } -{\sin x \over \cos x} = {1 - \sin^2 \over \cos x \times \sin x} = {\cos ^2x \over \cos x \times \sin x} ={ \cos x \over \sin x} = \cot x\]

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