Solve.
8x – 5 ≥ 27

a. x ≥ 4
b. x ≥ 11/4
c. x ≤ 4
d. x ≤ 11/4

Question

Solve.
8x – 5 ≥ 27  

  a.  x ≥ 4
  b.  x ≥ 11/4
  c.  x ≤ 4
  d.  x ≤ 11/4

anonymous · Answer

just like if it was an equal sign solve for x

anonymous · Answer

/\ what he/she said

anonymous · Answer

c?

anonymous · Answer

you don't have any negatives that you will multiply or divide both sides by so the greater than or equal to sign will not move.

anonymous · Answer

attachment

anonymous · Answer

8x - 5  ≥ 27
    + 5     +5  (Add 5 to both side)

5+5 cancels out, you now have 8x/8 and 32/5. So, C. c.  x ≤ 4

anonymous · Answer

$$8x-5\ge27 $$
       +5     +5
$$8x \ge32$$
divide both sides by 8
$$x \ge32/8$$

x$$\ge4$$

anonymous · Answer

if it was a negative 8"" instead of positive then you would.....

$$-8x \ge32$$
divide by -8
$$x \le32\div-8$$

$$x \le-4$$

anonymous · Answer

thanks do you know how to graph for the inequality?

anonymous · Answer

–3x > 24

anonymous · Answer

do the same thing and divide both sides by (-3) 

"this flips the sign the other way"

$$x <-8$$

now i'm pretty sure it doesn't want you to graph it on a plot but i'll show you both that and number line

anonymous · Answer

attachment

anonymous · Answer

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