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OpenStudy (anonymous):
find all values of Θ for which sinΘ = -sqrt (1-cos^2Θ) on (0,2pi)
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OpenStudy (anonymous):
the fundamental law that is [sin²x + cos²x = 1] will help you that is the same as sin²x=1-cos²x
OpenStudy (anonymous):
\[\sin ^{2}\theta + \cos ^{2}\theta = 1\] Very important formula
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