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18,59_ divisible by 9.
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thank you
oops. sorry. wrong
The question is, how? If the sum of digits is divisible by 9, then the number is!\[1 + 8 + 5 + 9 +\underline{} \ \text{is divisible by 9.}\]
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In other words, \(23 + \underline{}\) is divisible by \(9\).
Now the multiples of \(9\) are \(9,18,27,36,45,54\cdots\). Suffice to say that \(23 + \underline{}\) cannot be more than \(32\) and less than \(23\).
@nikkifields Do you get it, or will simple words help?
i get thank yall
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