Question

two equal circles of radius 5 cm have two common tangent AB and CD which touch the circle on A, C and B, D respectively and if CD = 24 cm, find the length of AB.

Answer 1

interesting :)

Answer 2

can i know what did you attempt here?

Answer 3

can i know what was your attempt here?

Answer 4

in a traingle bcd, i apply pythagoras theorem

Answer 5

CD^2=BC^2+BD^2

Answer 6

but how you got CD?

Answer 7

it is given

Answer 8

24^2=BC^2+5^2

Answer 9

ok

Answer 10

ok you see for getting AB we need to take one more triangle.can you tell which one that will be?

Answer 11

i don't know

Answer 12

well try to think of a triangle containing AB

Answer 13

a right angled one

Answer 14

plse see this diagram..

Answer 15

yep i saw

Answer 16

do u think taking a triangle BCD is right

Answer 17

okay...wait ..the other triangle be ABC.

Answer 18

wait a sec...

Answer 19

to make things clear join OB

Answer 20

where O is centre

Answer 21

k

Answer 22

in btw hw did u get bcd as rt angled ? :P

Answer 23

that's why i m saying i m wrong , we can't take tr.BCD

Answer 24

ob n od shld b joined

Answer 25

yeh :)

Answer 26

join OA also

Answer 27

i will try my best to draw that

Answer 28

yea thn tk d triangle AOD

Answer 29

& thn apply d theorem

Answer 30

ad^2= oa^2+od^2

Answer 31

@msingh i hand over this one to her :) seeya

Answer 32

k

Answer 33

vat is value of AD and OA

Answer 34

oa is 5

Answer 35

how

Answer 36

OA is not a radius

Answer 37

well msing we need to use property of tangents from same point i guess

Answer 38

lemme try this on properly ...

Answer 39

*on paper

Answer 40

draw a segment joining the centers.

Answer 41

nice one @sirm3d