Question

describe the roots 2x^2-x-3=0

Answer 1

\[\Delta = b^2 - 4ac\]
\[x _{1,2} = \frac{ -b \pm \sqrt{\Delta} }{2a}\]
In this case a=2 b=-1 c=-3
Do you want more help or you can pick it up from here?

Answer 2

more help

Answer 3

First find \[\Delta\] using the first formula.

Answer 4

okay after what do you do?

Answer 5

After that put \[\Delta\] in the second formula and then solve using + and - separately

Answer 6

then?