factor the expression. problem in comments. best answer ill become a fan.

Question

anonymous · Answer

$$81z^{2}+36z+4$$

anonymous · Answer

You can always use the quadratic formula.

anonymous · Answer

There are many ways to do it.

anonymous · Answer

my teacher didnt explain it and my parents cant do math.

anonymous · Answer

$$
81z^{2}+36z+4 \
81z^2+24z+8z+4 \
81z^2+18z+18z+4 \
9z(9z+2)+2(9z+2) \
(9z+2)^2
$$

campbell_st · Answer

this is a perfect square

$$(?z)^2 = 81z^2$$

whats the value of the ? above..?

and what is the value of $ below

$$($)^2 = 4$$

then is  the middle term 

 $$2 \times (?z) \times ($) = 36z$$

if all these conditions are met

your factorisation is 

$$(?z + $)^2 = 81z^2 + 36z + 4$$

hope this helps