Question

factor the expression. problem in comments. best answer ill become a fan.

Answer 1

\[81z^{2}+36z+4\]

Answer 2

You can always use the quadratic formula.

Answer 3

There are many ways to do it.

Answer 4

my teacher didnt explain it and my parents cant do math.

Answer 5

\[
81z^{2}+36z+4 \\
81z^2+24z+8z+4 \\
81z^2+18z+18z+4 \\
9z(9z+2)+2(9z+2) \\
(9z+2)^2
\]

Answer 6

this is a perfect square

\[(?z)^2 = 81z^2\]

whats the value of the ? above..?

and what is the value of $ below

\[($)^2 = 4\]

then is the middle term

\[2 \times (?z) \times ($) = 36z\]

if all these conditions are met

your factorisation is

\[(?z + $)^2 = 81z^2 + 36z + 4\]

hope this helps