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got it trig functions.
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Um,Do you have a question,We can work on ?
Wow,It's already up. Time moves so fast......
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|dw:1358605958708:dw|
\[tan(15)=\frac{200}{x}\] \[x=\frac{200}{tan(15)}\] \[tan(30)=\frac{200}{x'}\] \[x'=\frac{200}{tan(30)}\] \[\Delta x=x-x'\]
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depending on what angle
yea you got dat right
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