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3(x+2/5) = x - 1/3
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\[3\left( x+\frac{ 2 }{ 5 } \right)=x-\frac{ 1 }{ 3 }\] Distribute the 3 to get: \[3x+\frac{ 6 }{ 5 } = x-\frac{ 1 }{ 3 }\] Subtract the x and combine like terms to get: \[(3x-x)+\frac{ 6 }{ 5 }=-\frac{ 1 }{ 3 }\] Then, subtract the fraction on the left to get: \[(3x-x) = -\frac{ 1 }{ 3 }-\frac{ 6 }{ 5 }\] Next, divide by the number you get when you subtract x from 3x to solve for x, which is essentially your answer.
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