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x^2 < 3 Solve the inequality in terms of intervals. Interval notation Should be x < square root of 3, right? I tried this but it is wrong. It seems so simple, so where did I go wrong? Medal!
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is it x < + or - the square root of 3
This should be right! :) but on WebAssign it comes up wrong. I hate this program! Medal anyways!
\[x=\pm \sqrt{3}\] Factors are: \[(x-\sqrt{3})(x +\sqrt{3})\]
x^2 < 3 sqrt(x^2) < sqrt(3) |x| < sqrt(3) -sqrt(3) < x < sqrt(3)
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