The average length of some games has increased as indicated by the table on the next page. Let x be the number of years since 1980 and let y b the number of minutes an average game lasts beyond 2 hours.

∑x =110

∑y = 474

∑xy = 22998

∑x2 = 1540

∑y2 = 22998

CALCULATE COEFFICIENT OF CORREALTION

Question

The average length of some games has increased as indicated by the table on the next page.  Let x be the number of years since 1980 and let y b the number of minutes an average game lasts beyond 2 hours.

∑x =110

∑y = 474

∑xy = 22998

∑x2 = 1540

∑y2 = 22998

CALCULATE COEFFICIENT OF CORREALTION

anonymous · Answer

is n = to 2?

anonymous · Answer

i think i can solve it if 2 is n

dumbcow · Answer

here is formula using given stats .... as far as "n" it should be given http://en.wikipedia.org/wiki/Pearson_product-moment_correlation_coefficient#Mathematical_properties

anonymous · Answer

$$n(22998)-(110)(474)\div \sqrt{n(1540)-12100}-\sqrt{n(22998)-224676)}$$

anonymous · Answer

@dumbcow  my formula for least squares line is y=1.152x+34.73

anonymous · Answer

is it -.3902971292?   and if so..  how do you round it to 4 decimal places?