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OpenStudy (anonymous):
Find the value of cos θ for the angle shown.
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OpenStudy (anonymous):
We're missing the drawing!
OpenStudy (hba):
Is it involved with Vectors ?
OpenStudy (anonymous):
OpenStudy (hba):
\[Cos \theta= B/H\]
OpenStudy (anonymous):
how do i solve for the answer
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OpenStudy (anonymous):
This is how I would do it. cos(ø) = cos(-ø) So the cos of the smaller angle in the clockwise direction is the same as the big angle in the counterclockwise direction. cos = adjacent / hypotenuse adjacent = 4 and hypotenuse you can find through pythagorus. There's probably an easier way...
OpenStudy (anonymous):
so its cos θ = 4/7
OpenStudy (anonymous):
Yup!
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