Question

c+(4-3c)-2=0 help me solve this plez

Answer 1

Okay so use BIDMAS
Brackets
Indices (powers)
Division
Multiplication
Addition and finally then
Subtraction

i.e. first expand the bracket and take it from there

Answer 2

\[c+(4-3c)-2=0 => c+4-3c-2=0 => -2c+2 => 2c=2 => c=1\]

Answer 3

-2c+2=0 is what i meant to write on the third to last implication