Question

Help with series of revolutions question. Answer: 8/5 pi

Answer 1

I'm not sure how to get the answer.

Answer 2

\[\pi\int_{-1}^{1}\left((1)^2-(x^2)^2\right)\mathrm dx\]

Answer 3

Oh.....I think that's what I did wrong. I did \[(1 -x^2)^2\]

Answer 4

Just a sec.

Answer 5

Wow, I got the right answer! Thanks for finding my error!