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What is 3x^2-9x-12 when factored completely?
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what would go into twelve times that would add up to -9
but it says factored completely like (x^2-3x-4)
(3x-3)(x+4)
that isnt a choice :(
we're not done
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what?
3x^2-12x+3x-12
(3x^2-12x) (3x-12)
What is 3x^2-9x-12 when factored completely? 3(x^2 -3x -4) 3(x-4)(x+1)
each term has a coefficicient that is a multiple of 3 so start by taking 3 as a common factor \[3(x^2 + 3x - 4)\] now just factorise the quadratic
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Its 3(x-4)(x+1) thanks my_lyfe
no problem and your welcome!
thats not answer
the correct answer is 3(x + 4)(x -1) but its just a simple error
it says factor completely (3x+3)(x-4)
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Factor my answer and you will get your problem
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