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Mathematics 11 Online
OpenStudy (anonymous):

What is 3x^2-9x-12 when factored completely?

OpenStudy (anonymous):

what would go into twelve times that would add up to -9

OpenStudy (anonymous):

but it says factored completely like (x^2-3x-4)

OpenStudy (anonymous):

(3x-3)(x+4)

OpenStudy (anonymous):

that isnt a choice :(

OpenStudy (anonymous):

we're not done

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

3x^2-12x+3x-12

OpenStudy (anonymous):

(3x^2-12x) (3x-12)

OpenStudy (anonymous):

What is 3x^2-9x-12 when factored completely? 3(x^2 -3x -4) 3(x-4)(x+1)

OpenStudy (campbell_st):

each term has a coefficicient that is a multiple of 3 so start by taking 3 as a common factor \[3(x^2 + 3x - 4)\] now just factorise the quadratic

OpenStudy (anonymous):

Its 3(x-4)(x+1) thanks my_lyfe

OpenStudy (anonymous):

no problem and your welcome!

OpenStudy (anonymous):

thats not answer

OpenStudy (campbell_st):

the correct answer is 3(x + 4)(x -1) but its just a simple error

OpenStudy (anonymous):

it says factor completely (3x+3)(x-4)

OpenStudy (anonymous):

Factor my answer and you will get your problem

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