If a ball is thrown upward from the top of a building 192 ft high with an initial velocity of 48 ft/s, then the height h above the ground t seconds later will be

h = 192 + 48t − 16t^2.
During what time interval will the ball be at least 32 ft above the ground?

Question

If a ball is thrown upward from the top of a building 192 ft high with an initial velocity of 48 ft/s, then the height h above the ground t seconds later will be 

h = 192 + 48t − 16t^2.
 During what time interval will the ball be at least 32 ft above the ground?

anonymous · Answer

192 + 48t - 16t^2 >= 32
right?

then

|dw:1358727279938:dw|

but I don't know what to do from here?