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Mathematics 19 Online
OpenStudy (anonymous):

A box holding pennies, nickels and dimes contains thirteen coins with a total value of 83 cents. How many coins of each type are in the box? p+n+d=13 p+5n+10d=83 ---------------- -p1+p2 ------> p+n+d=13 4n+9d=70 ------------- The solution is (3, 4, 6) but how do I get to there?

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