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Mathematics 16 Online
OpenStudy (anonymous):

factor x^4-1

OpenStudy (blurbendy):

(x-1)(x+1)(x^2+1) x = 1 x = -1 x = i x = -i

OpenStudy (anonymous):

could you then factor the x^2+1 to (x-1)(x+1) so that fully factored would be (x-1)(x+1)(x-1)(x+1)?

OpenStudy (blurbendy):

(x^2 +1) Factored is actually (x - i)(x + i)

OpenStudy (anonymous):

where does the i come from?

OpenStudy (mertsj):

x^2+1 is the sum of two squares and will not factor within the set of real numbers.

OpenStudy (anonymous):

gotcha thank you.

OpenStudy (mertsj):

yw

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